Base | Representation |
---|---|
bin | 1011111011001000000011… |
… | …0110110101000001110001 |
3 | 1201102100020110102110100201 |
4 | 2332302000312311001301 |
5 | 3204300100410402032 |
6 | 43514500251315201 |
7 | 2522123661446005 |
oct | 276620066650161 |
9 | 51370213373321 |
10 | 13110402044017 |
11 | 41a50aa191493 |
12 | 1578a7314bb01 |
13 | 7413c8561095 |
14 | 334792782705 |
15 | 17b071be88e7 |
hex | bec80db5071 |
13110402044017 has 2 divisors, whose sum is σ = 13110402044018. Its totient is φ = 13110402044016.
The previous prime is 13110402043997. The next prime is 13110402044041. The reversal of 13110402044017 is 71044020401131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9209306979856 + 3901095064161 = 3034684^2 + 1975119^2 .
It is a cyclic number.
It is not a de Polignac number, because 13110402044017 - 27 = 13110402043889 is a prime.
It is not a weakly prime, because it can be changed into another prime (13110402044317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555201022008 + 6555201022009.
It is an arithmetic number, because the mean of its divisors is an integer number (6555201022009).
Almost surely, 213110402044017 is an apocalyptic number.
It is an amenable number.
13110402044017 is a deficient number, since it is larger than the sum of its proper divisors (1).
13110402044017 is an equidigital number, since it uses as much as digits as its factorization.
13110402044017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2688, while the sum is 28.
Adding to 13110402044017 its reverse (71044020401131), we get a palindrome (84154422445148).
The spelling of 13110402044017 in words is "thirteen trillion, one hundred ten billion, four hundred two million, forty-four thousand, seventeen".
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