13110402044041 has 2 divisors, whose sum is σ = 13110402044042. Its totient is φ = 13110402044040.

The previous prime is 13110402044017. The next prime is 13110402044081. The reversal of 13110402044041 is 14044020401131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10368264760441 + 2742137283600 = 3219979^2 + 1655940^2 .

It is a cyclic number.

It is not a de Polignac number, because 13110402044041 - 2⁷ = 13110402043913 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13110402043997 and 13110402044015.

It is not a weakly prime, because it can be changed into another prime (13110402044081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555201022020 + 6555201022021.

It is an arithmetic number, because the mean of its divisors is an integer number (6555201022021).

Almost surely, 2^{13110402044041} is an apocalyptic number.

It is an amenable number.

13110402044041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110402044041 is an equidigital number, since it uses as much as digits as its factorization.

13110402044041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 13110402044041 its reverse (14044020401131), we get a palindrome (27154422445172).

The spelling of 13110402044041 in words is "thirteen trillion, one hundred ten billion, four hundred two million, forty-four thousand, forty-one".