Base | Representation |
---|---|
bin | 1011111011001000000011… |
… | …0110110101000110110011 |
3 | 1201102100020110102110210122 |
4 | 2332302000312311012303 |
5 | 3204300100410404324 |
6 | 43514500251320455 |
7 | 2522123661446645 |
oct | 276620066650663 |
9 | 51370213373718 |
10 | 13110402044339 |
11 | 41a50aa191756 |
12 | 1578a7315012b |
13 | 7413c8561282 |
14 | 334792782895 |
15 | 17b071be8a5e |
hex | bec80db51b3 |
13110402044339 has 2 divisors, whose sum is σ = 13110402044340. Its totient is φ = 13110402044338.
The previous prime is 13110402044329. The next prime is 13110402044359. The reversal of 13110402044339 is 93344020401131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13110402044339 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13110402044299 and 13110402044308.
It is not a weakly prime, because it can be changed into another prime (13110402044329) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555201022169 + 6555201022170.
It is an arithmetic number, because the mean of its divisors is an integer number (6555201022170).
Almost surely, 213110402044339 is an apocalyptic number.
13110402044339 is a deficient number, since it is larger than the sum of its proper divisors (1).
13110402044339 is an equidigital number, since it uses as much as digits as its factorization.
13110402044339 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 35.
The spelling of 13110402044339 in words is "thirteen trillion, one hundred ten billion, four hundred two million, forty-four thousand, three hundred thirty-nine".
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