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13110402044339 is a prime number
BaseRepresentation
bin1011111011001000000011…
…0110110101000110110011
31201102100020110102110210122
42332302000312311012303
53204300100410404324
643514500251320455
72522123661446645
oct276620066650663
951370213373718
1013110402044339
1141a50aa191756
121578a7315012b
137413c8561282
14334792782895
1517b071be8a5e
hexbec80db51b3

13110402044339 has 2 divisors, whose sum is σ = 13110402044340. Its totient is φ = 13110402044338.

The previous prime is 13110402044329. The next prime is 13110402044359. The reversal of 13110402044339 is 93344020401131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13110402044339 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13110402044299 and 13110402044308.

It is not a weakly prime, because it can be changed into another prime (13110402044329) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555201022169 + 6555201022170.

It is an arithmetic number, because the mean of its divisors is an integer number (6555201022170).

Almost surely, 213110402044339 is an apocalyptic number.

13110402044339 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110402044339 is an equidigital number, since it uses as much as digits as its factorization.

13110402044339 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 35.

The spelling of 13110402044339 in words is "thirteen trillion, one hundred ten billion, four hundred two million, forty-four thousand, three hundred thirty-nine".