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1311040344453 = 3728918641799
BaseRepresentation
bin10011000101000000000…
…110000001000110000101
311122100000122201001122120
4103011000012001012011
5132440002312010303
62442141132320153
7163501542025500
oct23050006010605
94570018631576
101311040344453
11466011106404
12192108913059
13968274a9338
144765195c137
15241832d3553
hex13140181185

1311040344453 has 12 divisors (see below), whose sum is σ = 2033450330400. Its totient is φ = 749165911032.

The previous prime is 1311040344409. The next prime is 1311040344457. The reversal of 1311040344453 is 3544430401131.

It is not a de Polignac number, because 1311040344453 - 214 = 1311040328069 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311040344457) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 4459320753 + ... + 4459321046.

It is an arithmetic number, because the mean of its divisors is an integer number (169454194200).

Almost surely, 21311040344453 is an apocalyptic number.

It is an amenable number.

1311040344453 is a deficient number, since it is larger than the sum of its proper divisors (722409985947).

1311040344453 is an equidigital number, since it uses as much as digits as its factorization.

1311040344453 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8918641816 (or 8918641809 counting only the distinct ones).

The product of its (nonzero) digits is 34560, while the sum is 33.

Adding to 1311040344453 its reverse (3544430401131), we get a palindrome (4855470745584).

The spelling of 1311040344453 in words is "one trillion, three hundred eleven billion, forty million, three hundred forty-four thousand, four hundred fifty-three".

Divisors: 1 3 7 21 49 147 8918641799 26755925397 62430492593 187291477779 437013448151 1311040344453