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13110403510403 is a prime number
BaseRepresentation
bin1011111011001000000011…
…1100011011000010000011
31201102100020120011221212022
42332302000330123002003
53204300101244313103
643514500342552055
72522124010064123
oct276620074330203
951370216157768
1013110403510403
1141a50aaaa3181
121578a7373862b
137413c8955674
14334792a44c83
1517b071dd8138
hexbec80f1b083

13110403510403 has 2 divisors, whose sum is σ = 13110403510404. Its totient is φ = 13110403510402.

The previous prime is 13110403510397. The next prime is 13110403510417. The reversal of 13110403510403 is 30401530401131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13110403510403 - 222 = 13110399316099 is a prime.

It is not a weakly prime, because it can be changed into another prime (13110403510433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555201755201 + 6555201755202.

It is an arithmetic number, because the mean of its divisors is an integer number (6555201755202).

Almost surely, 213110403510403 is an apocalyptic number.

13110403510403 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110403510403 is an equidigital number, since it uses as much as digits as its factorization.

13110403510403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 13110403510403 its reverse (30401530401131), we get a palindrome (43511933911534).

The spelling of 13110403510403 in words is "thirteen trillion, one hundred ten billion, four hundred three million, five hundred ten thousand, four hundred three".