Base | Representation |
---|---|
bin | 10011000101000000010… |
… | …001010011001011101011 |
3 | 11122100000212021022210220 |
4 | 103011000101103023223 |
5 | 132440004041131443 |
6 | 2442141315541123 |
7 | 163501606124442 |
oct | 23050021231353 |
9 | 4570025238726 |
10 | 1311043302123 |
11 | 466012846565 |
12 | 1921098ba7a3 |
13 | 96827ca3639 |
14 | 476520cbd59 |
15 | 241836b9a83 |
hex | 131404532eb |
1311043302123 has 32 divisors (see below), whose sum is σ = 1847503257600. Its totient is φ = 825286958496.
The previous prime is 1311043302109. The next prime is 1311043302143. The reversal of 1311043302123 is 3212033401131.
It is not a de Polignac number, because 1311043302123 - 229 = 1310506431211 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1311043302093 and 1311043302102.
It is not an unprimeable number, because it can be changed into a prime (1311043302143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 32724138 + ... + 32764176.
It is an arithmetic number, because the mean of its divisors is an integer number (57734476800).
Almost surely, 21311043302123 is an apocalyptic number.
1311043302123 is a deficient number, since it is larger than the sum of its proper divisors (536459955477).
1311043302123 is a wasteful number, since it uses less digits than its factorization.
1311043302123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 46151.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 1311043302123 its reverse (3212033401131), we get a palindrome (4523076703254).
The spelling of 1311043302123 in words is "one trillion, three hundred eleven billion, forty-three million, three hundred two thousand, one hundred twenty-three".
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