Base | Representation |
---|---|
bin | 1011111011001000001010… |
… | …1101010011110101111110 |
3 | 1201102100022121212102120221 |
4 | 2332302002231103311332 |
5 | 3204300131333300410 |
6 | 43514503321131554 |
7 | 2522124516445441 |
oct | 276620255236576 |
9 | 51370277772527 |
10 | 13110433103230 |
11 | 41a5115775761 |
12 | 1578a81629bba |
13 | 741401b17208 |
14 | 334796949658 |
15 | 17b0747d14da |
hex | bec82b53d7e |
13110433103230 has 16 divisors (see below), whose sum is σ = 23599650652560. Its totient is φ = 5243979670912.
The previous prime is 13110433103227. The next prime is 13110433103239. The reversal of 13110433103230 is 3230133401131.
It is a junction number, because it is equal to n+sod(n) for n = 13110433103195 and 13110433103204.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13110433103239) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23911675 + ... + 24453814.
It is an arithmetic number, because the mean of its divisors is an integer number (1474978165785).
Almost surely, 213110433103230 is an apocalyptic number.
13110433103230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13110433103230 is a deficient number, since it is larger than the sum of its proper divisors (10489217549330).
13110433103230 is a wasteful number, since it uses less digits than its factorization.
13110433103230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 48392603.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 13110433103230 its reverse (3230133401131), we get a palindrome (16340566504361).
The spelling of 13110433103230 in words is "thirteen trillion, one hundred ten billion, four hundred thirty-three million, one hundred three thousand, two hundred thirty".
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