Base | Representation |
---|---|
bin | 10011000101000000010… |
… | …001010111111000010011 |
3 | 11122100000212022022012111 |
4 | 103011000101113320103 |
5 | 132440004042240423 |
6 | 2442141320210151 |
7 | 163501606234516 |
oct | 23050021277023 |
9 | 4570025268174 |
10 | 1311043321363 |
11 | 466012859a66 |
12 | 192109909957 |
13 | 96827cac319 |
14 | 476520d4d7d |
15 | 241836c060d |
hex | 13140457e13 |
1311043321363 has 2 divisors, whose sum is σ = 1311043321364. Its totient is φ = 1311043321362.
The previous prime is 1311043321321. The next prime is 1311043321429. The reversal of 1311043321363 is 3631233401131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1311043321363 - 213 = 1311043313171 is a prime.
It is not a weakly prime, because it can be changed into another prime (1311043321963) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655521660681 + 655521660682.
It is an arithmetic number, because the mean of its divisors is an integer number (655521660682).
Almost surely, 21311043321363 is an apocalyptic number.
1311043321363 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311043321363 is an equidigital number, since it uses as much as digits as its factorization.
1311043321363 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11664, while the sum is 31.
Adding to 1311043321363 its reverse (3631233401131), we get a palindrome (4942276722494).
The spelling of 1311043321363 in words is "one trillion, three hundred eleven billion, forty-three million, three hundred twenty-one thousand, three hundred sixty-three".
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