Base | Representation |
---|---|
bin | 11101110011110100011111… |
… | …111000001001000001011011 |
3 | 122012012110101212010112210111 |
4 | 131303310133320021001123 |
5 | 114141003313322133430 |
6 | 1142500311333425151 |
7 | 36420660351560554 |
oct | 3563643770110133 |
9 | 565173355115714 |
10 | 131104411521115 |
11 | 3885708346733a |
12 | 12854ab619b1b7 |
13 | 58201292c8486 |
14 | 24536b74dd32b |
15 | 10254d74abc2a |
hex | 773d1fe0905b |
131104411521115 has 16 divisors (see below), whose sum is σ = 159506854684128. Its totient is φ = 103429631344896.
The previous prime is 131104411521101. The next prime is 131104411521247. The reversal of 131104411521115 is 511125114401131.
It is a happy number.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131104411521115 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 27545557 + ... + 31952566.
It is an arithmetic number, because the mean of its divisors is an integer number (9969178417758).
Almost surely, 2131104411521115 is an apocalyptic number.
131104411521115 is a deficient number, since it is larger than the sum of its proper divisors (28402443163013).
131104411521115 is an equidigital number, since it uses as much as digits as its factorization.
131104411521115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 59504238.
The product of its (nonzero) digits is 2400, while the sum is 31.
Adding to 131104411521115 its reverse (511125114401131), we get a palindrome (642229525922246).
The spelling of 131104411521115 in words is "one hundred thirty-one trillion, one hundred four billion, four hundred eleven million, five hundred twenty-one thousand, one hundred fifteen".
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