Base | Representation |
---|---|
bin | 1011111011001000001100… |
… | …1100111110011010010101 |
3 | 1201102100100012111011011211 |
4 | 2332302003030332122111 |
5 | 3204300140444412203 |
6 | 43514504215101421 |
7 | 2522124650140210 |
oct | 276620314763225 |
9 | 51370305434154 |
10 | 13110441404053 |
11 | 41a511a425244 |
12 | 1578a84371871 |
13 | 741403762546 |
14 | 334797aaa777 |
15 | 17b0753c0c6d |
hex | bec8333e695 |
13110441404053 has 8 divisors (see below), whose sum is σ = 14983399286208. Its totient is φ = 11237492942304.
The previous prime is 13110441404051. The next prime is 13110441404089. The reversal of 13110441404053 is 35040414401131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13110441404053 - 21 = 13110441404051 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13110441404051) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 933225 + ... + 5204977.
It is an arithmetic number, because the mean of its divisors is an integer number (1872924910776).
Almost surely, 213110441404053 is an apocalyptic number.
It is an amenable number.
13110441404053 is a deficient number, since it is larger than the sum of its proper divisors (1872957882155).
13110441404053 is an equidigital number, since it uses as much as digits as its factorization.
13110441404053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4710203.
The product of its (nonzero) digits is 11520, while the sum is 31.
Adding to 13110441404053 its reverse (35040414401131), we get a palindrome (48150855805184).
The spelling of 13110441404053 in words is "thirteen trillion, one hundred ten billion, four hundred forty-one million, four hundred four thousand, fifty-three".
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