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13110441535355 = 56733896119327
BaseRepresentation
bin1011111011001000001100…
…1101011110011101111011
31201102100100012201211021212
42332302003031132131323
53204300141013112410
643514504221553335
72522124651225053
oct276620315363573
951370305654255
1013110441535355
1141a511a50495a
121578a8441584b
137414037aa238
14334797b02563
1517b0753e9b05
hexbec8335e77b

13110441535355 has 8 divisors (see below), whose sum is σ = 15755906562432. Its totient is φ = 10472768748288.

The previous prime is 13110441535349. The next prime is 13110441535409. The reversal of 13110441535355 is 55353514401131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13110441535355 - 212 = 13110441531259 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1948056299 + ... + 1948063028.

It is an arithmetic number, because the mean of its divisors is an integer number (1969488320304).

Almost surely, 213110441535355 is an apocalyptic number.

13110441535355 is a deficient number, since it is larger than the sum of its proper divisors (2645465027077).

13110441535355 is an equidigital number, since it uses as much as digits as its factorization.

13110441535355 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3896120005.

The product of its (nonzero) digits is 270000, while the sum is 41.

Adding to 13110441535355 its reverse (55353514401131), we get a palindrome (68463955936486).

The spelling of 13110441535355 in words is "thirteen trillion, one hundred ten billion, four hundred forty-one million, five hundred thirty-five thousand, three hundred fifty-five".

Divisors: 1 5 673 3365 3896119327 19480596635 2622088307071 13110441535355