Base | Representation |
---|---|
bin | 10011000101000000011… |
… | …011101001111001111111 |
3 | 11122100001001101020102112 |
4 | 103011000123221321333 |
5 | 132440010240013024 |
6 | 2442141454044235 |
7 | 163501641161462 |
oct | 23050033517177 |
9 | 4570031336375 |
10 | 1311046016639 |
11 | 46601432aa67 |
12 | 19210a7a967b |
13 | 96828714068 |
14 | 476525d72d9 |
15 | 24183a5400e |
hex | 131406e9e7f |
1311046016639 has 2 divisors, whose sum is σ = 1311046016640. Its totient is φ = 1311046016638.
The previous prime is 1311046016569. The next prime is 1311046016681. The reversal of 1311046016639 is 9366106401131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1311046016639 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1311046016596 and 1311046016605.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311046016939) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655523008319 + 655523008320.
It is an arithmetic number, because the mean of its divisors is an integer number (655523008320).
Almost surely, 21311046016639 is an apocalyptic number.
1311046016639 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311046016639 is an equidigital number, since it uses as much as digits as its factorization.
1311046016639 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69984, while the sum is 41.
The spelling of 1311046016639 in words is "one trillion, three hundred eleven billion, forty-six million, sixteen thousand, six hundred thirty-nine".
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