Base | Representation |
---|---|
bin | 10011000101000000110… |
… | …100100000010111011011 |
3 | 11122100001111122012200012 |
4 | 103011000310200113123 |
5 | 132440013421444123 |
6 | 2442142245432135 |
7 | 163502050433324 |
oct | 23050064402733 |
9 | 4570044565605 |
10 | 1311052531163 |
11 | 466017a7a471 |
12 | 192110a0b64b |
13 | 96829b852cb |
14 | 4765341144b |
15 | 241843de378 |
hex | 13140d205db |
1311052531163 has 2 divisors, whose sum is σ = 1311052531164. Its totient is φ = 1311052531162.
The previous prime is 1311052531111. The next prime is 1311052531189. The reversal of 1311052531163 is 3611352501131.
It is a strong prime.
It is an emirp because it is prime and its reverse (3611352501131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1311052531163 - 212 = 1311052527067 is a prime.
It is a super-2 number, since 2×13110525311632 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1311052534163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655526265581 + 655526265582.
It is an arithmetic number, because the mean of its divisors is an integer number (655526265582).
Almost surely, 21311052531163 is an apocalyptic number.
1311052531163 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311052531163 is an equidigital number, since it uses as much as digits as its factorization.
1311052531163 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8100, while the sum is 32.
The spelling of 1311052531163 in words is "one trillion, three hundred eleven billion, fifty-two million, five hundred thirty-one thousand, one hundred sixty-three".
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