1311054243341 has 4 divisors (see below), whose sum is σ = 1316494302684. Its totient is φ = 1305614184000.

The previous prime is 1311054243313. The next prime is 1311054243391. The reversal of 1311054243341 is 1433424501131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 379788712900 + 931265530441 = 616270^2 + 965021^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311054243341 - 2¹⁸ = 1311053981197 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311054243298 and 1311054243307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311054243311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2720029310 + ... + 2720029791.

It is an arithmetic number, because the mean of its divisors is an integer number (329123575671).

Almost surely, 2^{1311054243341} is an apocalyptic number.

It is an amenable number.

1311054243341 is a deficient number, since it is larger than the sum of its proper divisors (5440059343).

1311054243341 is an equidigital number, since it uses as much as digits as its factorization.

1311054243341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5440059342.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 1311054243341 its reverse (1433424501131), we get a palindrome (2744478744472).

The spelling of 1311054243341 in words is "one trillion, three hundred eleven billion, fifty-four million, two hundred forty-three thousand, three hundred forty-one".