Base | Representation |
---|---|
bin | 10011000101000001010… |
… | …110000011001101101001 |
3 | 11122100002010011222001212 |
4 | 103011001112003031221 |
5 | 132440023144342044 |
6 | 2442143202122505 |
7 | 163502215246316 |
oct | 23050126031551 |
9 | 4570063158055 |
10 | 1311061324649 |
11 | 466021a3610a |
12 | 192113950435 |
13 | 9682b94395b |
14 | 4765465dd0d |
15 | 24185079a9e |
hex | 13141583369 |
1311061324649 has 2 divisors, whose sum is σ = 1311061324650. Its totient is φ = 1311061324648.
The previous prime is 1311061324633. The next prime is 1311061324669. The reversal of 1311061324649 is 9464231601131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1302093234649 + 8968090000 = 1141093^2 + 94700^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311061324649 - 24 = 1311061324633 is a prime.
It is not a weakly prime, because it can be changed into another prime (1311061324669) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655530662324 + 655530662325.
It is an arithmetic number, because the mean of its divisors is an integer number (655530662325).
Almost surely, 21311061324649 is an apocalyptic number.
It is an amenable number.
1311061324649 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311061324649 is an equidigital number, since it uses as much as digits as its factorization.
1311061324649 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 93312, while the sum is 41.
The spelling of 1311061324649 in words is "one trillion, three hundred eleven billion, sixty-one million, three hundred twenty-four thousand, six hundred forty-nine".
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