131109401 has 2 divisors, whose sum is σ = 131109402. Its totient is φ = 131109400.

The previous prime is 131109397. The next prime is 131109403. The reversal of 131109401 is 104901131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129846025 + 1263376 = 11395^2 + 1124^2 .

It is an emirp because it is prime and its reverse (104901131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131109401 - 2² = 131109397 is a prime.

Together with 131109403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (131109403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65554700 + 65554701.

It is an arithmetic number, because the mean of its divisors is an integer number (65554701).

Almost surely, 2^131109401 is an apocalyptic number.

It is an amenable number.

131109401 is a deficient number, since it is larger than the sum of its proper divisors (1).

131109401 is an equidigital number, since it uses as much as digits as its factorization.

131109401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 20.

The square root of 131109401 is about 11450.3013497462. The cubic root of 131109401 is about 508.0166477794.

The spelling of 131109401 in words is "one hundred thirty-one million, one hundred nine thousand, four hundred one".