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1311100222141 is a prime number
BaseRepresentation
bin10011000101000011101…
…010011011101010111101
311122100011211101011101201
4103011003222123222331
5132440113124102031
62442151111535501
7163503200003143
oct23050352335275
94570154334351
101311100222141
114660419933a6
1219212498a591
1396836a12718
14476598a7593
15241886aed61
hex13143a9babd

1311100222141 has 2 divisors, whose sum is σ = 1311100222142. Its totient is φ = 1311100222140.

The previous prime is 1311100222087. The next prime is 1311100222253. The reversal of 1311100222141 is 1412220011131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1063897354116 + 247202868025 = 1031454^2 + 497195^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311100222141 - 225 = 1311066667709 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311100222541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655550111070 + 655550111071.

It is an arithmetic number, because the mean of its divisors is an integer number (655550111071).

Almost surely, 21311100222141 is an apocalyptic number.

It is an amenable number.

1311100222141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311100222141 is an equidigital number, since it uses as much as digits as its factorization.

1311100222141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 1311100222141 its reverse (1412220011131), we get a palindrome (2723320233272).

The spelling of 1311100222141 in words is "one trillion, three hundred eleven billion, one hundred million, two hundred twenty-two thousand, one hundred forty-one".