Base | Representation |
---|---|
bin | 10011000101000011101… |
… | …101011011110010111011 |
3 | 11122100011212212010212201 |
4 | 103011003231123302323 |
5 | 132440113324242313 |
6 | 2442151140451031 |
7 | 163503206461345 |
oct | 23050355336273 |
9 | 4570155763781 |
10 | 1311101009083 |
11 | 466042380668 |
12 | 1921250a9a77 |
13 | 96836c29978 |
14 | 47659a30295 |
15 | 241887b80dd |
hex | 13143b5bcbb |
1311101009083 has 2 divisors, whose sum is σ = 1311101009084. Its totient is φ = 1311101009082.
The previous prime is 1311101009069. The next prime is 1311101009089. The reversal of 1311101009083 is 3809001011131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1311101009083 is a prime.
It is not a weakly prime, because it can be changed into another prime (1311101009089) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655550504541 + 655550504542.
It is an arithmetic number, because the mean of its divisors is an integer number (655550504542).
Almost surely, 21311101009083 is an apocalyptic number.
1311101009083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311101009083 is an equidigital number, since it uses as much as digits as its factorization.
1311101009083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 28.
The spelling of 1311101009083 in words is "one trillion, three hundred eleven billion, one hundred one million, nine thousand, eighty-three".
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