Base | Representation |
---|---|
bin | 10011000101000011101… |
… | …101011100010001001111 |
3 | 11122100011212212020112120 |
4 | 103011003231130101033 |
5 | 132440113324323043 |
6 | 2442151140504023 |
7 | 163503206500116 |
oct | 23050355342117 |
9 | 4570155766476 |
10 | 1311101011023 |
11 | 466042382071 |
12 | 1921250ab013 |
13 | 96836c2a80b |
14 | 47659a30c7d |
15 | 241887b8983 |
hex | 13143b5c44f |
1311101011023 has 8 divisors (see below), whose sum is σ = 1748141463600. Its totient is φ = 874063949568.
The previous prime is 1311101011019. The next prime is 1311101011067. The reversal of 1311101011023 is 3201101011131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1311101011023 - 22 = 1311101011019 is a prime.
It is a super-2 number, since 2×13111010110232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1311101010993 and 1311101011011.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311101011223) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 261823 + ... + 1640351.
It is an arithmetic number, because the mean of its divisors is an integer number (218517682950).
Almost surely, 21311101011023 is an apocalyptic number.
1311101011023 is a deficient number, since it is larger than the sum of its proper divisors (437040452577).
1311101011023 is a wasteful number, since it uses less digits than its factorization.
1311101011023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1695561.
The product of its (nonzero) digits is 18, while the sum is 15.
Adding to 1311101011023 its reverse (3201101011131), we get a palindrome (4512202022154).
The spelling of 1311101011023 in words is "one trillion, three hundred eleven billion, one hundred one million, eleven thousand, twenty-three".
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