Base | Representation |
---|---|
bin | 11101110011111001111001… |
… | …100000011101110000001111 |
3 | 122012020000100222102112202210 |
4 | 131303321321200131300033 |
5 | 114141102202304400221 |
6 | 1142503111000121503 |
7 | 36421254143030313 |
oct | 3563717140356017 |
9 | 565200328375683 |
10 | 131110210231311 |
11 | 38859589704113 |
12 | 12856054166293 |
13 | 5820841777b3c |
14 | 2453aa76b1b43 |
15 | 10257265d3276 |
hex | 773e7981dc0f |
131110210231311 has 4 divisors (see below), whose sum is σ = 174813613641752. Its totient is φ = 87406806820872.
The previous prime is 131110210231271. The next prime is 131110210231327. The reversal of 131110210231311 is 113132012011131.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 131110210231311 - 226 = 131110143122447 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131110210231331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21851701705216 + ... + 21851701705221.
It is an arithmetic number, because the mean of its divisors is an integer number (43703403410438).
Almost surely, 2131110210231311 is an apocalyptic number.
131110210231311 is a deficient number, since it is larger than the sum of its proper divisors (43703403410441).
131110210231311 is an equidigital number, since it uses as much as digits as its factorization.
131110210231311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 43703403410440.
The product of its (nonzero) digits is 108, while the sum is 21.
Adding to 131110210231311 its reverse (113132012011131), we get a palindrome (244242222242442).
The spelling of 131110210231311 in words is "one hundred thirty-one trillion, one hundred ten billion, two hundred ten million, two hundred thirty-one thousand, three hundred eleven".
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