1311102652471 has 2 divisors, whose sum is σ = 1311102652472. Its totient is φ = 1311102652470.

The previous prime is 1311102652399. The next prime is 1311102652537. The reversal of 1311102652471 is 1742562011131.

It is a strong prime.

It is an emirp because it is prime and its reverse (1742562011131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1311102652471 - 2²⁹ = 1310565781559 is a prime.

It is a super-3 number, since 3×1311102652471³ (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311102652571) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655551326235 + 655551326236.

It is an arithmetic number, because the mean of its divisors is an integer number (655551326236).

Almost surely, 2^{1311102652471} is an apocalyptic number.

1311102652471 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311102652471 is an equidigital number, since it uses as much as digits as its factorization.

1311102652471 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10080, while the sum is 34.

The spelling of 1311102652471 in words is "one trillion, three hundred eleven billion, one hundred two million, six hundred fifty-two thousand, four hundred seventy-one".