Base | Representation |
---|---|
bin | 1011111011001010011001… |
… | …0110100010000101010101 |
3 | 1201102101212022010102102200 |
4 | 2332302212112202011111 |
5 | 3204302342431041041 |
6 | 43515042522355113 |
7 | 2522145400442343 |
oct | 276624626420525 |
9 | 51371768112380 |
10 | 13111031112021 |
11 | 41a53a22935a7 |
12 | 157900995ba99 |
13 | 74149899667b |
14 | 334812134993 |
15 | 17b0ac0591b6 |
hex | beca65a2155 |
13111031112021 has 6 divisors (see below), whose sum is σ = 18938156050710. Its totient is φ = 8740687408008.
The previous prime is 13111031112019. The next prime is 13111031112061. The reversal of 13111031112021 is 12021113011131.
13111031112021 is a `hidden beast` number, since 1 + 311 + 1 + 0 + 311 + 1 + 20 + 21 = 666.
13111031112021 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in only one way, i.e., 12636531944100 + 474499167921 = 3554790^2 + 688839^2 .
It is not a de Polignac number, because 13111031112021 - 21 = 13111031112019 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13111031111985 and 13111031112003.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13111031112061) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 728390617326 + ... + 728390617343.
It is an arithmetic number, because the mean of its divisors is an integer number (3156359341785).
Almost surely, 213111031112021 is an apocalyptic number.
It is an amenable number.
13111031112021 is a deficient number, since it is larger than the sum of its proper divisors (5827124938689).
13111031112021 is a wasteful number, since it uses less digits than its factorization.
13111031112021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1456781234675 (or 1456781234672 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 18.
Adding to 13111031112021 its reverse (12021113011131), we get a palindrome (25132144123152).
The spelling of 13111031112021 in words is "thirteen trillion, one hundred eleven billion, thirty-one million, one hundred twelve thousand, twenty-one".
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