13111031212123 has 4 divisors (see below), whose sum is σ = 14119572074608. Its totient is φ = 12102490349640.

The previous prime is 13111031212079. The next prime is 13111031212207. The reversal of 13111031212123 is 32121213011131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13111031212123 - 2⁹ = 13111031211611 is a prime.

It is a super-3 number, since 3×13111031212123³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13111031212094 and 13111031212103.

It is not an unprimeable number, because it can be changed into a prime (13111031242123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 504270431223 + ... + 504270431248.

It is an arithmetic number, because the mean of its divisors is an integer number (3529893018652).

Almost surely, 2^{13111031212123} is an apocalyptic number.

13111031212123 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

13111031212123 is a deficient number, since it is larger than the sum of its proper divisors (1008540862485).

13111031212123 is a wasteful number, since it uses less digits than its factorization.

13111031212123 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1008540862484.

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 13111031212123 its reverse (32121213011131), we get a palindrome (45232244223254).

The spelling of 13111031212123 in words is "thirteen trillion, one hundred eleven billion, thirty-one million, two hundred twelve thousand, one hundred twenty-three".