13111041341003 has 4 divisors (see below), whose sum is σ = 13199034907200. Its totient is φ = 13023047774808.

The previous prime is 13111041340979. The next prime is 13111041341017. The reversal of 13111041341003 is 30014314011131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13111041341003 - 2⁴² = 8712994829899 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13111041341003.

It is not an unprimeable number, because it can be changed into a prime (13111041041003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43996782875 + ... + 43996783172.

It is an arithmetic number, because the mean of its divisors is an integer number (3299758726800).

Almost surely, 2^{13111041341003} is an apocalyptic number.

13111041341003 is a deficient number, since it is larger than the sum of its proper divisors (87993566197).

13111041341003 is an equidigital number, since it uses as much as digits as its factorization.

13111041341003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 87993566196.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 13111041341003 its reverse (30014314011131), we get a palindrome (43125355352134).

The spelling of 13111041341003 in words is "thirteen trillion, one hundred eleven billion, forty-one million, three hundred forty-one thousand, three".