13111044211555 has 4 divisors (see below), whose sum is σ = 15733253053872. Its totient is φ = 10488835369240.

The previous prime is 13111044211547. The next prime is 13111044211561. The reversal of 13111044211555 is 55511244011131.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13111044211555 - 2³ = 13111044211547 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13111044211555.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1311104421151 + ... + 1311104421160.

It is an arithmetic number, because the mean of its divisors is an integer number (3933313263468).

Almost surely, 2^{13111044211555} is an apocalyptic number.

13111044211555 is a deficient number, since it is larger than the sum of its proper divisors (2622208842317).

13111044211555 is an equidigital number, since it uses as much as digits as its factorization.

13111044211555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2622208842316.

The product of its (nonzero) digits is 12000, while the sum is 34.

Adding to 13111044211555 its reverse (55511244011131), we get a palindrome (68622288222686).

The spelling of 13111044211555 in words is "thirteen trillion, one hundred eleven billion, forty-four million, two hundred eleven thousand, five hundred fifty-five".