Base | Representation |
---|---|
bin | 1011111011001010101001… |
… | …1110011101111110010011 |
3 | 1201102102001010022121010222 |
4 | 2332302222132131332103 |
5 | 3204303013134114303 |
6 | 43515053433343255 |
7 | 2522150200521152 |
oct | 276625236357623 |
9 | 51372033277128 |
10 | 13111100301203 |
11 | 41a5428350443 |
12 | 1579028b67b2b |
13 | 7414aa110108 |
14 | 33481b3c5599 |
15 | 17b0b3174938 |
hex | becaa79df93 |
13111100301203 has 2 divisors, whose sum is σ = 13111100301204. Its totient is φ = 13111100301202.
The previous prime is 13111100301149. The next prime is 13111100301223. The reversal of 13111100301203 is 30210300111131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13111100301203 is a prime.
It is a super-2 number, since 2×131111003012032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13111100301223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555550150601 + 6555550150602.
It is an arithmetic number, because the mean of its divisors is an integer number (6555550150602).
Almost surely, 213111100301203 is an apocalyptic number.
13111100301203 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111100301203 is an equidigital number, since it uses as much as digits as its factorization.
13111100301203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 13111100301203 its reverse (30210300111131), we get a palindrome (43321400412334).
The spelling of 13111100301203 in words is "thirteen trillion, one hundred eleven billion, one hundred million, three hundred one thousand, two hundred three".
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