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13111102229287 is a prime number
BaseRepresentation
bin1011111011001010101010…
…0101110100101100100111
31201102102001020221112222111
42332302222211310230213
53204303014132314122
643515053542541451
72522150223101326
oct276625245645447
951372036845874
1013111102229287
1141a5429447aa7
121579029737887
137414aa6368aa
1433481b7680bd
1517b0b3405d77
hexbecaa974b27

13111102229287 has 2 divisors, whose sum is σ = 13111102229288. Its totient is φ = 13111102229286.

The previous prime is 13111102229263. The next prime is 13111102229339. The reversal of 13111102229287 is 78292220111131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13111102229287 is a prime.

It is a super-2 number, since 2×131111022292872 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13111102223287) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555551114643 + 6555551114644.

It is an arithmetic number, because the mean of its divisors is an integer number (6555551114644).

Almost surely, 213111102229287 is an apocalyptic number.

13111102229287 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111102229287 is an equidigital number, since it uses as much as digits as its factorization.

13111102229287 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24192, while the sum is 40.

The spelling of 13111102229287 in words is "thirteen trillion, one hundred eleven billion, one hundred two million, two hundred twenty-nine thousand, two hundred eighty-seven".