Base | Representation |
---|---|
bin | 1011111011001010101010… |
… | …0101110100101100100111 |
3 | 1201102102001020221112222111 |
4 | 2332302222211310230213 |
5 | 3204303014132314122 |
6 | 43515053542541451 |
7 | 2522150223101326 |
oct | 276625245645447 |
9 | 51372036845874 |
10 | 13111102229287 |
11 | 41a5429447aa7 |
12 | 1579029737887 |
13 | 7414aa6368aa |
14 | 33481b7680bd |
15 | 17b0b3405d77 |
hex | becaa974b27 |
13111102229287 has 2 divisors, whose sum is σ = 13111102229288. Its totient is φ = 13111102229286.
The previous prime is 13111102229263. The next prime is 13111102229339. The reversal of 13111102229287 is 78292220111131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13111102229287 is a prime.
It is a super-2 number, since 2×131111022292872 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13111102223287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555551114643 + 6555551114644.
It is an arithmetic number, because the mean of its divisors is an integer number (6555551114644).
Almost surely, 213111102229287 is an apocalyptic number.
13111102229287 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111102229287 is an equidigital number, since it uses as much as digits as its factorization.
13111102229287 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24192, while the sum is 40.
The spelling of 13111102229287 in words is "thirteen trillion, one hundred eleven billion, one hundred two million, two hundred twenty-nine thousand, two hundred eighty-seven".
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