Base | Representation |
---|---|
bin | 11101110011111010101111… |
… | …010101001000011010110000 |
3 | 122012020002200220120122002200 |
4 | 131303322233111020122300 |
5 | 114141111024441330000 |
6 | 1142503340334343200 |
7 | 36421315416265461 |
oct | 3563725725103260 |
9 | 565202626518080 |
10 | 131111113230000 |
11 | 38859a023a4422 |
12 | 1285626665ab00 |
13 | 58209568813a7 |
14 | 2453b515acd68 |
15 | 102577aa03500 |
hex | 773eaf5486b0 |
131111113230000 has 600 divisors, whose sum is σ = 485894653564320. Its totient is φ = 32933967360000.
The previous prime is 131111113229939. The next prime is 131111113230001. The reversal of 131111113230000 is 32311111131.
131111113230000 is a `hidden beast` number, since 1 + 311 + 11 + 11 + 32 + 300 + 0 + 0 = 666.
It is a tau number, because it is divible by the number of its divisors (600).
It is a Harshad number since it is a multiple of its sum of digits (18).
It is not an unprimeable number, because it can be changed into a prime (131111113230001) by changing a digit.
It is a polite number, since it can be written in 119 ways as a sum of consecutive naturals, for example, 106397389 + ... + 107622611.
Almost surely, 2131111113230000 is an apocalyptic number.
131111113230000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131111113230000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (242947326782160).
131111113230000 is an abundant number, since it is smaller than the sum of its proper divisors (354783540334320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131111113230000 is a wasteful number, since it uses less digits than its factorization.
131111113230000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1225327 (or 1225303 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 18.
Adding to 131111113230000 its reverse (32311111131), we get a palindrome (131143424341131).
The spelling of 131111113230000 in words is "one hundred thirty-one trillion, one hundred eleven billion, one hundred thirteen million, two hundred thirty thousand".
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