Base | Representation |
---|---|
bin | 1011111011001010101101… |
… | …0011101001100100111111 |
3 | 1201102102002002112212211101 |
4 | 2332302223103221210333 |
5 | 3204303030221223432 |
6 | 43515055052233531 |
7 | 2522150430154021 |
oct | 276625323514477 |
9 | 51372062485741 |
10 | 13111114242367 |
11 | 41a5435202669 |
12 | 157903176b8a7 |
13 | 7414acc8181b |
14 | 33481d1b4011 |
15 | 17b0b44ca4e7 |
hex | becab4e993f |
13111114242367 has 2 divisors, whose sum is σ = 13111114242368. Its totient is φ = 13111114242366.
The previous prime is 13111114242319. The next prime is 13111114242377. The reversal of 13111114242367 is 76324241111131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13111114242367 - 235 = 13076754503999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13111114242377) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555557121183 + 6555557121184.
It is an arithmetic number, because the mean of its divisors is an integer number (6555557121184).
Almost surely, 213111114242367 is an apocalyptic number.
13111114242367 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111114242367 is an equidigital number, since it uses as much as digits as its factorization.
13111114242367 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 24192, while the sum is 37.
Adding to 13111114242367 its reverse (76324241111131), we get a palindrome (89435355353498).
The spelling of 13111114242367 in words is "thirteen trillion, one hundred eleven billion, one hundred fourteen million, two hundred forty-two thousand, three hundred sixty-seven".
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