131111251121 has 2 divisors, whose sum is σ = 131111251122. Its totient is φ = 131111251120.

The previous prime is 131111251087. The next prime is 131111251127. The reversal of 131111251121 is 121152111131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110931628096 + 20179623025 = 333064^2 + 142055^2 .

It is an emirp because it is prime and its reverse (121152111131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131111251121 is a prime.

It is a super-3 number, since 3×131111251121³ (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131111251093 and 131111251102.

It is not a weakly prime, because it can be changed into another prime (131111251127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65555625560 + 65555625561.

It is an arithmetic number, because the mean of its divisors is an integer number (65555625561).

Almost surely, 2^131111251121 is an apocalyptic number.

It is an amenable number.

131111251121 is a deficient number, since it is larger than the sum of its proper divisors (1).

131111251121 is an equidigital number, since it uses as much as digits as its factorization.

131111251121 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 60, while the sum is 20.

Adding to 131111251121 its reverse (121152111131), we get a palindrome (252263362252).

The spelling of 131111251121 in words is "one hundred thirty-one billion, one hundred eleven million, two hundred fifty-one thousand, one hundred twenty-one".