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131111251127 is a prime number
BaseRepresentation
bin111101000011011010…
…1101110110010110111
3110112102100221122120222
41322012311232302313
54122003440014002
6140122013044555
712321026150363
oct1720665566267
9415370848528
10131111251127
115067097959a
12214b0a8675b
13c49619468c
1464bacd62a3
1536256bd1a2
hex1e86d6ecb7

131111251127 has 2 divisors, whose sum is σ = 131111251128. Its totient is φ = 131111251126.

The previous prime is 131111251121. The next prime is 131111251133. The reversal of 131111251127 is 721152111131.

It is a balanced prime because it is at equal distance from previous prime (131111251121) and next prime (131111251133).

It is an emirp because it is prime and its reverse (721152111131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131111251127 - 236 = 62391774391 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131111251096 and 131111251105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131111251121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65555625563 + 65555625564.

It is an arithmetic number, because the mean of its divisors is an integer number (65555625564).

Almost surely, 2131111251127 is an apocalyptic number.

131111251127 is a deficient number, since it is larger than the sum of its proper divisors (1).

131111251127 is an equidigital number, since it uses as much as digits as its factorization.

131111251127 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 420, while the sum is 26.

Adding to 131111251127 its reverse (721152111131), we get a palindrome (852263362258).

The spelling of 131111251127 in words is "one hundred thirty-one billion, one hundred eleven million, two hundred fifty-one thousand, one hundred twenty-seven".