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1311113121211 is a prime number
BaseRepresentation
bin10011000101000100011…
…011101000110110111011
311122100012201122111121001
4103011010123220312323
5132440124424334321
62442152252225431
7163503414435565
oct23050433506673
94570181574531
101311113121211
114660491a3693
1219212916b277
13968395aa9ca
144765b4a4335
15241898abc91
hex131446e8dbb

1311113121211 has 2 divisors, whose sum is σ = 1311113121212. Its totient is φ = 1311113121210.

The previous prime is 1311113121209. The next prime is 1311113121247. The reversal of 1311113121211 is 1121213111131.

It is a m-pointer prime, because the next prime (1311113121247) can be obtained adding 1311113121211 to its product of digits (36).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1311113121211 - 21 = 1311113121209 is a prime.

It is a super-2 number, since 2×13111131212112 (a number of 25 digits) contains 22 as substring.

Together with 1311113121209, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1311113121511) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655556560605 + 655556560606.

It is an arithmetic number, because the mean of its divisors is an integer number (655556560606).

Almost surely, 21311113121211 is an apocalyptic number.

1311113121211 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311113121211 is an equidigital number, since it uses as much as digits as its factorization.

1311113121211 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 36, while the sum is 19.

Adding to 1311113121211 its reverse (1121213111131), we get a palindrome (2432326232342).

The spelling of 1311113121211 in words is "one trillion, three hundred eleven billion, one hundred thirteen million, one hundred twenty-one thousand, two hundred eleven".