1311114511121 has 2 divisors, whose sum is σ = 1311114511122. Its totient is φ = 1311114511120.

The previous prime is 1311114511111. The next prime is 1311114511241. The reversal of 1311114511121 is 1211154111131.

It is a m-pointer prime, because the next prime (1311114511241) can be obtained adding 1311114511121 to its product of digits (120).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1304198260225 + 6916250896 = 1142015^2 + 83164^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311114511121 is a prime.

It is a super-2 number, since 2×1311114511121² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1311114511111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655557255560 + 655557255561.

It is an arithmetic number, because the mean of its divisors is an integer number (655557255561).

Almost surely, 2^{1311114511121} is an apocalyptic number.

It is an amenable number.

1311114511121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311114511121 is an equidigital number, since it uses as much as digits as its factorization.

1311114511121 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 120, while the sum is 23.

Adding to 1311114511121 its reverse (1211154111131), we get a palindrome (2522268622252).

The spelling of 1311114511121 in words is "one trillion, three hundred eleven billion, one hundred fourteen million, five hundred eleven thousand, one hundred twenty-one".