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13111145224351 is a prime number
BaseRepresentation
bin1011111011001010110100…
…1001110101100010011111
31201102102011020211221010021
42332302231021311202133
53204303111134134401
643515102120253011
72522151254412346
oct276625511654237
951372136757107
1013111145224351
1141a5450743909
121579040011167
137414b650b765
1433482335ab5d
1517b0b709a2a1
hexbecad27589f

13111145224351 has 2 divisors, whose sum is σ = 13111145224352. Its totient is φ = 13111145224350.

The previous prime is 13111145224277. The next prime is 13111145224403. The reversal of 13111145224351 is 15342254111131.

It is a strong prime.

It is an emirp because it is prime and its reverse (15342254111131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13111145224351 - 243 = 4315052202143 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13111145254351) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555572612175 + 6555572612176.

It is an arithmetic number, because the mean of its divisors is an integer number (6555572612176).

Almost surely, 213111145224351 is an apocalyptic number.

13111145224351 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111145224351 is an equidigital number, since it uses as much as digits as its factorization.

13111145224351 is an evil number, because the sum of its binary digits is even.

The product of its digits is 14400, while the sum is 34.

Adding to 13111145224351 its reverse (15342254111131), we get a palindrome (28453399335482).

The spelling of 13111145224351 in words is "thirteen trillion, one hundred eleven billion, one hundred forty-five million, two hundred twenty-four thousand, three hundred fifty-one".