Base | Representation |
---|---|
bin | 1011111011001010110100… |
… | …1001110101100010011111 |
3 | 1201102102011020211221010021 |
4 | 2332302231021311202133 |
5 | 3204303111134134401 |
6 | 43515102120253011 |
7 | 2522151254412346 |
oct | 276625511654237 |
9 | 51372136757107 |
10 | 13111145224351 |
11 | 41a5450743909 |
12 | 1579040011167 |
13 | 7414b650b765 |
14 | 33482335ab5d |
15 | 17b0b709a2a1 |
hex | becad27589f |
13111145224351 has 2 divisors, whose sum is σ = 13111145224352. Its totient is φ = 13111145224350.
The previous prime is 13111145224277. The next prime is 13111145224403. The reversal of 13111145224351 is 15342254111131.
It is a strong prime.
It is an emirp because it is prime and its reverse (15342254111131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13111145224351 - 243 = 4315052202143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13111145254351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555572612175 + 6555572612176.
It is an arithmetic number, because the mean of its divisors is an integer number (6555572612176).
Almost surely, 213111145224351 is an apocalyptic number.
13111145224351 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111145224351 is an equidigital number, since it uses as much as digits as its factorization.
13111145224351 is an evil number, because the sum of its binary digits is even.
The product of its digits is 14400, while the sum is 34.
Adding to 13111145224351 its reverse (15342254111131), we get a palindrome (28453399335482).
The spelling of 13111145224351 in words is "thirteen trillion, one hundred eleven billion, one hundred forty-five million, two hundred twenty-four thousand, three hundred fifty-one".
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