Base | Representation |
---|---|
bin | 10011000101000100100… |
… | …110110101001101111101 |
3 | 11122100012221011120120111 |
4 | 103011010212311031331 |
5 | 132440131202233141 |
6 | 2442152435150021 |
7 | 163503451406254 |
oct | 23050446651575 |
9 | 4570187146514 |
10 | 1311116055421 |
11 | 46604a918157 |
12 | 19212a145311 |
13 | 9683a097423 |
14 | 4765ba2979b |
15 | 24189c8b381 |
hex | 131449b537d |
1311116055421 has 2 divisors, whose sum is σ = 1311116055422. Its totient is φ = 1311116055420.
The previous prime is 1311116055307. The next prime is 1311116055449. The reversal of 1311116055421 is 1245506111131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1045324252921 + 265791802500 = 1022411^2 + 515550^2 .
It is an emirp because it is prime and its reverse (1245506111131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1311116055421 - 239 = 761360241533 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311116055721) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655558027710 + 655558027711.
It is an arithmetic number, because the mean of its divisors is an integer number (655558027711).
Almost surely, 21311116055421 is an apocalyptic number.
It is an amenable number.
1311116055421 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311116055421 is an equidigital number, since it uses as much as digits as its factorization.
1311116055421 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3600, while the sum is 31.
The spelling of 1311116055421 in words is "one trillion, three hundred eleven billion, one hundred sixteen million, fifty-five thousand, four hundred twenty-one".
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