Base | Representation |
---|---|
bin | 111101000011011100… |
… | …0100101101001110001 |
3 | 110112102102100201000012 |
4 | 1322012320211221301 |
5 | 4122004133000423 |
6 | 140122041104305 |
7 | 12321035420123 |
oct | 1720670455161 |
9 | 415372321005 |
10 | 131112000113 |
11 | 50671340296 |
12 | 214b1188095 |
13 | c496397573 |
14 | 64bb04d213 |
15 | 36257ba078 |
hex | 1e86e25a71 |
131112000113 has 2 divisors, whose sum is σ = 131112000114. Its totient is φ = 131112000112.
The previous prime is 131112000091. The next prime is 131112000139. The reversal of 131112000113 is 311000211131.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 103731017329 + 27380982784 = 322073^2 + 165472^2 .
It is a cyclic number.
It is not a de Polignac number, because 131112000113 - 28 = 131111999857 is a prime.
It is not a weakly prime, because it can be changed into another prime (131112000713) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65556000056 + 65556000057.
It is an arithmetic number, because the mean of its divisors is an integer number (65556000057).
Almost surely, 2131112000113 is an apocalyptic number.
It is an amenable number.
131112000113 is a deficient number, since it is larger than the sum of its proper divisors (1).
131112000113 is an equidigital number, since it uses as much as digits as its factorization.
131112000113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 14.
Adding to 131112000113 its reverse (311000211131), we get a palindrome (442112211244).
The spelling of 131112000113 in words is "one hundred thirty-one billion, one hundred twelve million, one hundred thirteen", and thus it is an aban number.
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