Base | Representation |
---|---|
bin | 111101000011011100… |
… | …1000000100000010111 |
3 | 110112102102120021212220 |
4 | 1322012321000200113 |
5 | 4122004200010403 |
6 | 140122043313423 |
7 | 12321036355602 |
oct | 1720671004027 |
9 | 415372507786 |
10 | 131112110103 |
11 | 50671405997 |
12 | 214b121b873 |
13 | c496405650 |
14 | 64bb07b339 |
15 | 36257dc953 |
hex | 1e86e40817 |
131112110103 has 16 divisors (see below), whose sum is σ = 188276682720. Its totient is φ = 80678744064.
The previous prime is 131112110093. The next prime is 131112110111. The reversal of 131112110103 is 301011211131.
It is not a de Polignac number, because 131112110103 - 214 = 131112093719 is a prime.
It is a super-2 number, since 2×1311121101032 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131112110603) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 488175 + ... + 707487.
It is an arithmetic number, because the mean of its divisors is an integer number (11767292670).
Almost surely, 2131112110103 is an apocalyptic number.
131112110103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
131112110103 is a deficient number, since it is larger than the sum of its proper divisors (57164572617).
131112110103 is a wasteful number, since it uses less digits than its factorization.
131112110103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 234658.
The product of its (nonzero) digits is 18, while the sum is 15.
Adding to 131112110103 its reverse (301011211131), we get a palindrome (432123321234).
The spelling of 131112110103 in words is "one hundred thirty-one billion, one hundred twelve million, one hundred ten thousand, one hundred three".
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