13111211120221 has 4 divisors (see below), whose sum is σ = 13111333930332. Its totient is φ = 13111088310112.

The previous prime is 13111211120219. The next prime is 13111211120233. The reversal of 13111211120221 is 12202111211131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6046853131225 + 7064357988996 = 2459035^2 + 2657886^2 .

It is a cyclic number.

It is not a de Polignac number, because 13111211120221 - 2¹ = 13111211120219 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13111211130221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61244776 + ... + 61458481.

It is an arithmetic number, because the mean of its divisors is an integer number (3277833482583).

Almost surely, 2^{13111211120221} is an apocalyptic number.

It is an amenable number.

13111211120221 is a deficient number, since it is larger than the sum of its proper divisors (122810111).

13111211120221 is a wasteful number, since it uses less digits than its factorization.

13111211120221 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 122810110.

The product of its (nonzero) digits is 48, while the sum is 19.

Adding to 13111211120221 its reverse (12202111211131), we get a palindrome (25313322331352).

It can be divided in two parts, 1311121 and 1120221, that added together give a palindrome (2431342).

The spelling of 13111211120221 in words is "thirteen trillion, one hundred eleven billion, two hundred eleven million, one hundred twenty thousand, two hundred twenty-one".