1311121131 has 4 divisors (see below), whose sum is σ = 1748161512. Its totient is φ = 874080752.

The previous prime is 1311121111. The next prime is 1311121153. The reversal of 1311121131 is 1311211131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1311211131 = 3 ⋅437070377.

It is a cyclic number.

It is not a de Polignac number, because 1311121131 - 2⁶ = 1311121067 is a prime.

It is a super-2 number, since 2×1311121131² = 3438077240309438322, which contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1311121131.

It is not an unprimeable number, because it can be changed into a prime (1311121111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218520186 + ... + 218520191.

It is an arithmetic number, because the mean of its divisors is an integer number (437040378).

Almost surely, 2^1311121131 is an apocalyptic number.

1311121131 is a deficient number, since it is larger than the sum of its proper divisors (437040381).

1311121131 is an equidigital number, since it uses as much as digits as its factorization.

1311121131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 437040380.

The product of its digits is 18, while the sum is 15.

The square root of 1311121131 is about 36209.4066645672. The cubic root of 1311121131 is about 1094.4962358210.

Adding to 1311121131 its reverse (1311211131), we get a palindrome (2622332262).

Subtracting 1311121131 from its reverse (1311211131), we obtain a square (90000 = 300²).

The spelling of 1311121131 in words is "one billion, three hundred eleven million, one hundred twenty-one thousand, one hundred thirty-one".