Base | Representation |
---|---|
bin | 111101000011011100… |
… | …1000011001100010111 |
3 | 110112102102120211222121 |
4 | 1322012321003030113 |
5 | 4122004200333421 |
6 | 140122043440411 |
7 | 12321036432646 |
oct | 1720671031427 |
9 | 415372524877 |
10 | 131112121111 |
11 | 50671413194 |
12 | 214b1226107 |
13 | c49640a66a |
14 | 64bb08135d |
15 | 36257e0d41 |
hex | 1e86e43317 |
131112121111 has 4 divisors (see below), whose sum is σ = 131120610192. Its totient is φ = 131103632032.
The previous prime is 131112121109. The next prime is 131112121123. The reversal of 131112121111 is 111121211131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131112121111 - 21 = 131112121109 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131112121141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4221331 + ... + 4252276.
It is an arithmetic number, because the mean of its divisors is an integer number (32780152548).
Almost surely, 2131112121111 is an apocalyptic number.
131112121111 is a deficient number, since it is larger than the sum of its proper divisors (8489081).
131112121111 is an equidigital number, since it uses as much as digits as its factorization.
131112121111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8489080.
The product of its digits is 12, while the sum is 16.
Adding to 131112121111 its reverse (111121211131), we get a palindrome (242233332242).
The spelling of 131112121111 in words is "one hundred thirty-one billion, one hundred twelve million, one hundred twenty-one thousand, one hundred eleven".
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