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13111223046793 is a prime number
BaseRepresentation
bin1011111011001011000111…
…0010101101001010001001
31201102102100200021201102221
42332302301302231022021
53204303241044444133
643515113540254041
72522153221036054
oct276626162551211
951372320251387
1013111223046793
1141a5490667a83
1215790620a1321
137414c9688941
1433482d817a9b
1517b0bdd1da2d
hexbecb1cad289

13111223046793 has 2 divisors, whose sum is σ = 13111223046794. Its totient is φ = 13111223046792.

The previous prime is 13111223046787. The next prime is 13111223046821. The reversal of 13111223046793 is 39764032211131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12510453888144 + 600769158649 = 3537012^2 + 775093^2 .

It is a cyclic number.

It is not a de Polignac number, because 13111223046793 - 225 = 13111189492361 is a prime.

It is not a weakly prime, because it can be changed into another prime (13111223046763) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555611523396 + 6555611523397.

It is an arithmetic number, because the mean of its divisors is an integer number (6555611523397).

Almost surely, 213111223046793 is an apocalyptic number.

It is an amenable number.

13111223046793 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111223046793 is an equidigital number, since it uses as much as digits as its factorization.

13111223046793 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 163296, while the sum is 43.

The spelling of 13111223046793 in words is "thirteen trillion, one hundred eleven billion, two hundred twenty-three million, forty-six thousand, seven hundred ninety-three".