Base | Representation |
---|---|
bin | 1011111011001011000111… |
… | …0010111101001010001010 |
3 | 1201102102100200102001100020 |
4 | 2332302301302331022022 |
5 | 3204303241104043310 |
6 | 43515113541521310 |
7 | 2522153221431120 |
oct | 276626162751212 |
9 | 51372320361306 |
10 | 13111223112330 |
11 | 41a5490702242 |
12 | 1579062113236 |
13 | 7414c96ac715 |
14 | 33482d833910 |
15 | 17b0bdd33170 |
hex | becb1cbd28a |
13111223112330 has 64 divisors (see below), whose sum is σ = 36011678976000. Its totient is φ = 2992728746304.
The previous prime is 13111223112311. The next prime is 13111223112343. The reversal of 13111223112330 is 3321132211131.
It is a self number, because there is not a number n which added to its sum of digits gives 13111223112330.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 42787080 + ... + 43092419.
It is an arithmetic number, because the mean of its divisors is an integer number (562682484000).
Almost surely, 213111223112330 is an apocalyptic number.
13111223112330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13111223112330 is an abundant number, since it is smaller than the sum of its proper divisors (22900455863670).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13111223112330 is a wasteful number, since it uses less digits than its factorization.
13111223112330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 85880243.
The product of its (nonzero) digits is 648, while the sum is 24.
Adding to 13111223112330 its reverse (3321132211131), we get a palindrome (16432355323461).
The spelling of 13111223112330 in words is "thirteen trillion, one hundred eleven billion, two hundred twenty-three million, one hundred twelve thousand, three hundred thirty".
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