13111254021 has 4 divisors (see below), whose sum is σ = 17481672032. Its totient is φ = 8740836012.

The previous prime is 13111254011. The next prime is 13111254043. The reversal of 13111254021 is 12045211131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13111254021 - 2⁵ = 13111253989 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13111254011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2185209001 + ... + 2185209006.

It is an arithmetic number, because the mean of its divisors is an integer number (4370418008).

Almost surely, 2^13111254021 is an apocalyptic number.

It is an amenable number.

13111254021 is a deficient number, since it is larger than the sum of its proper divisors (4370418011).

13111254021 is an equidigital number, since it uses as much as digits as its factorization.

13111254021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4370418010.

The product of its (nonzero) digits is 240, while the sum is 21.

Adding to 13111254021 its reverse (12045211131), we get a palindrome (25156465152).

The spelling of 13111254021 in words is "thirteen billion, one hundred eleven million, two hundred fifty-four thousand, twenty-one".