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131113035 = 32514591997
BaseRepresentation
bin1111101000010…
…10000001001011
3100010201020021100
413310022001023
5232031104120
621002112443
73151304514
oct764120113
9303636240
10131113035
1168012189
1237aab723
13212182a1
14135ada0b
15b79d490
hex7d0a04b

131113035 has 24 divisors (see below), whose sum is σ = 227532240. Its totient is φ = 69844032.

The previous prime is 131113019. The next prime is 131113069. The reversal of 131113035 is 530311131.

It is not a de Polignac number, because 131113035 - 24 = 131113019 is a prime.

It is a super-2 number, since 2×1311130352 = 34381255893822450, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131112999 and 131113017.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 64657 + ... + 66653.

It is an arithmetic number, because the mean of its divisors is an integer number (9480510).

Almost surely, 2131113035 is an apocalyptic number.

131113035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

131113035 is a deficient number, since it is larger than the sum of its proper divisors (96419205).

131113035 is a wasteful number, since it uses less digits than its factorization.

131113035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3467 (or 3464 counting only the distinct ones).

The product of its (nonzero) digits is 135, while the sum is 18.

The square root of 131113035 is about 11450.4600344266. The cubic root of 131113035 is about 508.0213413544.

Adding to 131113035 its reverse (530311131), we get a palindrome (661424166).

The spelling of 131113035 in words is "one hundred thirty-one million, one hundred thirteen thousand, thirty-five".

Divisors: 1 3 5 9 15 45 1459 1997 4377 5991 7295 9985 13131 17973 21885 29955 65655 89865 2913623 8740869 14568115 26222607 43704345 131113035