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1311130642553 = 23105295414159
BaseRepresentation
bin10011000101000101011…
…110011110100001111001
311122100020221121200100122
4103011011132132201321
5132440143421030203
62442154115543025
7163504016402324
oct23050536364171
94570227550318
101311130642553
11466058080736
12192132bbaa75
1396840103b74
144765d9457bb
152418b1bd538
hex1314579e879

1311130642553 has 8 divisors (see below), whose sum is σ = 1368266515200. Its totient is φ = 1254005619328.

The previous prime is 1311130642541. The next prime is 1311130642561. The reversal of 1311130642553 is 3552460311131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1311130642553 - 212 = 1311130638457 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1311130042553) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2464913 + ... + 2949246.

It is an arithmetic number, because the mean of its divisors is an integer number (171033314400).

Almost surely, 21311130642553 is an apocalyptic number.

It is an amenable number.

1311130642553 is a deficient number, since it is larger than the sum of its proper divisors (57135872647).

1311130642553 is a wasteful number, since it uses less digits than its factorization.

1311130642553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5424711.

The product of its (nonzero) digits is 32400, while the sum is 35.

Adding to 1311130642553 its reverse (3552460311131), we get a palindrome (4863590953684).

The spelling of 1311130642553 in words is "one trillion, three hundred eleven billion, one hundred thirty million, six hundred forty-two thousand, five hundred fifty-three".

Divisors: 1 23 10529 242167 5414159 124525657 57005680111 1311130642553