Base | Representation |
---|---|
bin | 10011000101000101011… |
… | …110011110101011001101 |
3 | 11122100020221121201011201 |
4 | 103011011132132223031 |
5 | 132440143421040044 |
6 | 2442154115545501 |
7 | 163504016404135 |
oct | 23050536365315 |
9 | 4570227551151 |
10 | 1311130643149 |
11 | 466058081128 |
12 | 192132bbb291 |
13 | 96840104212 |
14 | 4765d945ac5 |
15 | 2418b1bd7d4 |
hex | 1314579eacd |
1311130643149 has 2 divisors, whose sum is σ = 1311130643150. Its totient is φ = 1311130643148.
The previous prime is 1311130643143. The next prime is 1311130643261. The reversal of 1311130643149 is 9413460311131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1179493742025 + 131636901124 = 1086045^2 + 362818^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1311130643149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311130643143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655565321574 + 655565321575.
It is an arithmetic number, because the mean of its divisors is an integer number (655565321575).
Almost surely, 21311130643149 is an apocalyptic number.
It is an amenable number.
1311130643149 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311130643149 is an equidigital number, since it uses as much as digits as its factorization.
1311130643149 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23328, while the sum is 37.
The spelling of 1311130643149 in words is "one trillion, three hundred eleven billion, one hundred thirty million, six hundred forty-three thousand, one hundred forty-nine".
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