1311131000243 has 2 divisors, whose sum is σ = 1311131000244. Its totient is φ = 1311131000242.

The previous prime is 1311131000147. The next prime is 1311131000299. The reversal of 1311131000243 is 3420001311131.

It is a strong prime.

It is an emirp because it is prime and its reverse (3420001311131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1311131000243 - 2⁸ = 1311130999987 is a prime.

It is a super-3 number, since 3×1311131000243³ (a number of 37 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (1311131000743) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655565500121 + 655565500122.

It is an arithmetic number, because the mean of its divisors is an integer number (655565500122).

Almost surely, 2^{1311131000243} is an apocalyptic number.

1311131000243 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311131000243 is an equidigital number, since it uses as much as digits as its factorization.

1311131000243 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 1311131000243 its reverse (3420001311131), we get a palindrome (4731132311374).

The spelling of 1311131000243 in words is "one trillion, three hundred eleven billion, one hundred thirty-one million, two hundred forty-three", and thus it is an aban number.