1311131000147 has 2 divisors, whose sum is σ = 1311131000148. Its totient is φ = 1311131000146.

The previous prime is 1311130999987. The next prime is 1311131000243. The reversal of 1311131000147 is 7410001311131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1311131000147 - 2²⁴ = 1311114222931 is a prime.

It is not a weakly prime, because it can be changed into another prime (1311131005147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655565500073 + 655565500074.

It is an arithmetic number, because the mean of its divisors is an integer number (655565500074).

Almost surely, 2^{1311131000147} is an apocalyptic number.

1311131000147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311131000147 is an equidigital number, since it uses as much as digits as its factorization.

1311131000147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252, while the sum is 23.

Adding to 1311131000147 its reverse (7410001311131), we get a palindrome (8721132311278).

The spelling of 1311131000147 in words is "one trillion, three hundred eleven billion, one hundred thirty-one million, one hundred forty-seven", and thus it is an aban number.