13111310023 has 4 divisors (see below), whose sum is σ = 14984354320. Its totient is φ = 11238265728.

The previous prime is 13111309979. The next prime is 13111310029. The reversal of 13111310023 is 32001311131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13111310023 - 2⁹ = 13111309511 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13111309979 and 13111310006.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13111310029) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 936522138 + ... + 936522151.

It is an arithmetic number, because the mean of its divisors is an integer number (3746088580).

Almost surely, 2^13111310023 is an apocalyptic number.

13111310023 is a deficient number, since it is larger than the sum of its proper divisors (1873044297).

13111310023 is an equidigital number, since it uses as much as digits as its factorization.

13111310023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1873044296.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 13111310023 its reverse (32001311131), we get a palindrome (45112621154).

The spelling of 13111310023 in words is "thirteen billion, one hundred eleven million, three hundred ten thousand, twenty-three".