Base | Representation |
---|---|
bin | 11101110011111100100110… |
… | …111101100111111000001011 |
3 | 122012020021212210022001020210 |
4 | 131303330212331213320023 |
5 | 114141124132301131243 |
6 | 1142504311433452203 |
7 | 36421416230343612 |
oct | 3563744675477013 |
9 | 565207783261223 |
10 | 131113120333323 |
11 | 3885a8423528a7 |
12 | 12856726871063 |
13 | 5820bb66449ab |
14 | 2453ca1d96879 |
15 | 1025846d1a933 |
hex | 773f26f67e0b |
131113120333323 has 4 divisors (see below), whose sum is σ = 174817493777768. Its totient is φ = 87408746888880.
The previous prime is 131113120333301. The next prime is 131113120333367. The reversal of 131113120333323 is 323333021311131.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 131113120333323 - 25 = 131113120333291 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131113120323323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21852186722218 + ... + 21852186722223.
It is an arithmetic number, because the mean of its divisors is an integer number (43704373444442).
Almost surely, 2131113120333323 is an apocalyptic number.
131113120333323 is a deficient number, since it is larger than the sum of its proper divisors (43704373444445).
131113120333323 is an equidigital number, since it uses as much as digits as its factorization.
131113120333323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43704373444444.
The product of its (nonzero) digits is 8748, while the sum is 30.
Adding to 131113120333323 its reverse (323333021311131), we get a palindrome (454446141644454).
The spelling of 131113120333323 in words is "one hundred thirty-one trillion, one hundred thirteen billion, one hundred twenty million, three hundred thirty-three thousand, three hundred twenty-three".
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